(5-2x)(2x+1)=4x^2-25

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Solution for (5-2x)(2x+1)=4x^2-25 equation:


Simplifying
(5 + -2x)(2x + 1) = 4x2 + -25

Reorder the terms:
(5 + -2x)(1 + 2x) = 4x2 + -25

Multiply (5 + -2x) * (1 + 2x)
(5(1 + 2x) + -2x * (1 + 2x)) = 4x2 + -25
((1 * 5 + 2x * 5) + -2x * (1 + 2x)) = 4x2 + -25
((5 + 10x) + -2x * (1 + 2x)) = 4x2 + -25
(5 + 10x + (1 * -2x + 2x * -2x)) = 4x2 + -25
(5 + 10x + (-2x + -4x2)) = 4x2 + -25

Combine like terms: 10x + -2x = 8x
(5 + 8x + -4x2) = 4x2 + -25

Reorder the terms:
5 + 8x + -4x2 = -25 + 4x2

Solving
5 + 8x + -4x2 = -25 + 4x2

Solving for variable 'x'.

Reorder the terms:
5 + 25 + 8x + -4x2 + -4x2 = -25 + 4x2 + 25 + -4x2

Combine like terms: 5 + 25 = 30
30 + 8x + -4x2 + -4x2 = -25 + 4x2 + 25 + -4x2

Combine like terms: -4x2 + -4x2 = -8x2
30 + 8x + -8x2 = -25 + 4x2 + 25 + -4x2

Reorder the terms:
30 + 8x + -8x2 = -25 + 25 + 4x2 + -4x2

Combine like terms: -25 + 25 = 0
30 + 8x + -8x2 = 0 + 4x2 + -4x2
30 + 8x + -8x2 = 4x2 + -4x2

Combine like terms: 4x2 + -4x2 = 0
30 + 8x + -8x2 = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(15 + 4x + -4x2) = 0

Factor a trinomial.
2((5 + -2x)(3 + 2x)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(5 + -2x)' equal to zero and attempt to solve: Simplifying 5 + -2x = 0 Solving 5 + -2x = 0 Move all terms containing x to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -2x = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -2x = 0 + -5 -2x = 0 + -5 Combine like terms: 0 + -5 = -5 -2x = -5 Divide each side by '-2'. x = 2.5 Simplifying x = 2.5

Subproblem 2

Set the factor '(3 + 2x)' equal to zero and attempt to solve: Simplifying 3 + 2x = 0 Solving 3 + 2x = 0 Move all terms containing x to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + 2x = 0 + -3 Combine like terms: 3 + -3 = 0 0 + 2x = 0 + -3 2x = 0 + -3 Combine like terms: 0 + -3 = -3 2x = -3 Divide each side by '2'. x = -1.5 Simplifying x = -1.5

Solution

x = {2.5, -1.5}

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